Question

A solution S of sulfuric acid is prepared by dissolving 49g of H2SO4 in 500 mL of distilled water. Calculate the molar concentration of the solution

Answer 1

The density of H₂SO₄ is 1.83 g/cm³. Therefore, the volume of H₂SO₄ equals $\frac{49g}{1.83g/cm^3}=27mL$ , and the total volume of the resulting solution is 500 + 27 = 527 mL = 0.527 L.

Amount of H₂SO₄ in moles:

$n=\frac{49g}{98.1g/mol}=0.50 mol$

Therefore, the concentration is:

$C=\frac{0.50mol}{0.527L}=0.95M$

Answer: 0.95 M