Question

given the following solution of potassium permanganate: 

C=2 mol/L

V= 500 ml

a)calculate the volume needed to prepare another solution of potassium permanganate of concentration C=0.2mol/L and V=100mL.

b)50 mL of the prepared solution are taken and 150 mL of water are added. Calculate the new concentration of the solution.

Answer 1

a) V₁ = C₂*V₂/C₁ = 0.2*100/2 = 10 ml

b) C₂ = (C₁*V₁)/(V₁+V_water) = (2*50)/(50+150) = 0.5 mol/L