Answer to Question #151981 in Organic Chemistry for Asma Moosa

Question

Calculate the volume of ammonia gas (in mL) that will exactly neutralize 31.68 mL of a 0.215!M solution of sulfuric acid

Answer 1

$2NH_3 + H_2SO_4 = (NH4)_2SO_4$

The above is the balanced equation for the reaction of ammonia gas with sulfuric acid

number of moles of sulfuric acid = molar concentration × volume = 0.215 × 31.68/1000 = 0.0068 mol

from the reaction above,

1 mole of sulfuric acid reacts with 2 moles of ammonia gas

thus, 0.0068 mol of sulfuric acid reacts with 2 (0.0068) mol = 0.0136 mol

1 mole of a gas = 22.4dm³

0.0136 mol = x dm³

x = $\dfrac{0.0136×22.4}{1}$ = 0.305 dm³

0.305 dm³ = 0.305 × 1000 mL = 305 mL

Therefore, 305 mL of ammonia gas will exactly neutralize 31.68 mL.