Question

C6H12O6 + 6O2 -> 6CO2 + 6H2O. How many grams CO2 are formed from O.25 mole glucose

Answer 1

$C_6H_{12}O_6 + 6O_2 \to 6CO_2 + 6H_2O$

From the equation above,

1 mole of glucose forms 6 moles of CO2

1 mole of glucose = 264g (6 mol × 44g/mol) of CO2

0.25 moles of glucose = xg

x = $\dfrac{0.25×264}{1}$ = 66g

Therefore, 66 grams of CO2 are formed from O.25 mole glucose.