Question

A 3.0L flask contains 3.5mol of HI, 4 Moles of H2 and 0.3 mol of I2 in equilibrium.
Calculate the Kc of the reaction.
H2(g)+I2(g) HI(g)

Answer 1

$Kc = \frac{(HI)^r}{(H2)(I2)}$

$Kc = \frac{(1.6)\times(1.6)}{(1.33)(0,1)}$

= 10.11