Calculate the value of Kc from the following equilibrium concentrations: [FeNCS2+] Æ 1.84£10¡4 M,
[Fe3+] Æ 1.32£10¡3 M, and [SCN–] Æ 1.02£10¡3 M
Kc = [Fe(NCS)2+]/([Fe3+]*[SCN–]) = 1.84*10-4/(1.32*10-3 * 1.02*10-3) = 136.66
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments
Leave a comment