We know pH= -log [H+]
So, here pH = 5.44
So, -log [H+] = 5.44
Or, [H+] = 10^-5.44
= 3.63×10^-6 M
We also know that pH + pOH = 14
So, pOH = 14-pH
Or, pOH= 14-5.44
= 8.56
Now, -log[OH-] = pOH
OR,-log[OH-] = 8.56
Or, [OH-] = 10^-8.56
= 2.75×10^-9 M
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