100ml ,1 M OF sucrose solution when treated with charcol becomes 0.8M .Amount of sucrose adsorbed in moles is ?
100 mL = 0.1 L
Initial amount in moles:
1mol/L * 0.1L = 0.1 mol
Final amount in moles:
0.8mol/L * 0.1L = 0.08 mol
Therefore, the amount of sucrose adsorbed is 0.1 - 0.08 = 0.02 mol
Answer: 0.02 moles
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