Answer to Question #190285 in Inorganic Chemistry for Ravana

Question #190285

How many unpaired electrons are there in a strong field iron(II) octahedral complex


1
Expert's answer
2021-05-09T00:00:41-0400

There are zero unpaired electrons in strong field Fe(II) octahedral complex.



Electronic configuration of "Fe" is "\\space3d^6\\space4s^2"

Electronic configuration of "Fe(\\Iota\\Iota)" is "3d^6\\space 4s^0"

Because, 2 electrons are removed from "4s" orbital of the "Fe(\\Iota\\Iota)".

In a strong field, "d^6" electrons are split into "t_{2g}^6" and "e_g^0" . These 6 electrons in "t_{2g}" are paired. So there is no unpaired electron in the octahedral complex.


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