Question

If 4 moles of NH₃ (ammonia) and 3 moles of O₂ (oxygen gas) react in the reaction below, determine the EXCESS reactant. 4NH₃ + 5O₂ --> 4NO + 6H₂O

If 25.4 g of Al₂O₃ is reacted with 10.2 g of Fe, determine the LIMITING reactant. 4Al₂O₃ + 9Fe --> 3Fe₃O₄ +8Al

Answer 1

Ammonia is the excess reactant

$Moles (Al_2O_3) = \frac{25.4}{101.96}=0.25moles$

$$Moles(Fe) = \frac{10.2}{55.85}=0.18moles$$

Limiting reactant us Al₂O₃