. How many grams of sulfuric acid, H2SO4, can be obtained from 457 grams of iron ore if the ore is 73.0% by mass FeS? The reactions involved are given below. Reactions happen with the yield of 90.0%, 82.0% and 92.5% respectively 4 FeS + 7O2 → 2 Fe2O3 + 4 SO2 2 SO2 + O2 → 2 SO3 SO3 + H2O → H2SO4
. How many grams of sulfuric acid, H2SO4, can be obtained from 457 grams of iron ore if the ore is 73.0% by mass FeS? The reactions involved are given below. Reactions happen with the yield of 90.0%, 82.0% and 92.5% respectively 4 FeS + 7O2 → 2 Fe2O3 + 4 SO2 2 SO2 + O2 → 2 SO3 SO3 + H2O → H2SO4
Phosphoric acid can be prepared from phosphorus triiodide according to the reaction:
Pl3 (s) + H2O(l) -----------> H3PO3(aq) + HI(g)
If 150 g of PI3 (MM = 411.7 g/mol) is added to 250 mL of H2O (g/mol), d = 1.00 g/mL), Identify which will be limiting and excess reagents. ( How many grams of H3PO3 (MM = 97.99 g/mol) will be produced theoretically?
Phosphoric acid can be prepared from phosphorus triiodide according to the reaction:
Pl3 (s) + H2O(l) -----------> H3PO3(aq) + HI(g)
If 150 g of PI3 (MM = 411.7 g/mol) is added to 250 mL of H2O (g/mol), d = 1.00 g/mL), Identify which will be limiting and excess reagents.
How many grams of H3PO3 (MM = 97.99 g/mol) will be produced theoretically?
Phosphoric acid can be prepared from phosphorus triiodide according to the reaction:
Pl3 (s) + H2O(l) -----------> H3PO3(aq) + HI(g)
If 150 g of PI3 (MM = 411.7 g/mol) is added to 250 mL of H2O (g/mol), d = 1.00 g/mL), Identify which will be limiting and excess reagents.
What factors that can interfere the stock solution preparation?
Perhaps can you share the link because I want to refer there for reference
if 2000 mg of nano2 is dissolved in 2000 ml of distilled water, what is the concentration of no - in this solution in ppm?
Directions: Try to determine which column exerts greater partial pressure is greater by putting E on the blank if the column on the left is greater than the column on the right and putting Z on the blank if the column on the right is greater than the column on the left. 1. Ptotal = 0.83 atm Ptotal = 0.95 atm
X1 = 0.23 X2 = 0.19
Ptotal = 14 psi Ptotal = 10 psi
2. n1 = 0.2 mol n2 = 12 mol
ntotal = 0.3 mol ntotal = 16 mol
3. Ptotal = 20 kPa Ptotal = 0.95 atm
X1 = 0.87 X2 = 0.19
Ptotal = 101 kPa Ptotal = 110 kPa
4. n1 = 0.4 mol n2 = 5 mol
ntotal = 1.2 mol ntotal = 14 mol
Ptotal = 1.2 atm Ptotal = 110 kPa
5. n1 = 0.4 mol n2 = 5 mol
ntotal = 1.2 mol ntotal = 14 mol
6. Ptotal = 2.3 atm Ptotal = 3.4 atm
X1 = 0.23 X2 = 0.19
7. Ptotal = 0.83 atm Ptotal = 19 psi
X1 = 0.23 X2 = 0.19
Ptotal = 202 kPa Ptotal = 30 psi
8. n1 = 0.4 mol n2 = 5 mol
ntotal = 1.2 mol ntotal = 14 mol
9. Ptotal = 1.2 atm Ptotal = 3.4 atm
X1 = 0.5 X2 = 0.2
10. Ptotal = 6 MPa Ptotal = 5.3 MPa
X1 = 0.6 X2 = 0.5
The reaction of carbon disulfide with chlorine is as follows: CS2 (g) + 3 Cl2 (g) ⇋ CCl4 (g) + S2Cl2 (g) H = -238 kJ Predict the effect of the following changes to the system on the direction of equilibrium. a. The pressure on the system is doubled by halving the volume. b. CCl4 is removed as it is generated. c. Heat is added to the system.
A hypothetical acid HA has a dissociation constant 1.8 𝑥 10ିଷ. a. Write a balanced dissociation reaction of the acid b. Write the equilibrium constant expression for the acid c. If the initial concentration of the acid is 0.5 M, determine its hydrogen ion concentration. d. Calculate the ionization constant e. Comment on the strength of the acid.