. How many grams of sulfuric acid, H2SO4, can be obtained from 457 grams of iron ore if the ore is 73.0% by mass FeS? The reactions involved are given below. Reactions happen with the yield of 90.0%, 82.0% and 92.5% respectively 4 FeS + 7O2 → 2 Fe2O3 + 4 SO2 2 SO2 + O2 → 2 SO3 SO3 + H2O → H2SO4
Start by writing a balanced chemical equation for the partial ionization of the acid
"HA\n\n(aq]\n\n+\n\nH\n\n2\n\nO\n\n(l]\n\n\u21cc\n\nA\n\n\u2212\n\n(aq]\n\n+\n\nH\n\n3\n\nO\n\n+\n\n(aq]"
Notice that you have 1:1
mole ratios across the board. For every mole of acid that ionizes in aqueous solution, you get one mole of its conjugate base and one mole of hydronium ions, H3O+
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