Question

. How many grams of sulfuric acid, H2SO4, can be obtained from 457 grams of iron ore if the ore is 73.0% by mass FeS? The reactions involved are given below. Reactions happen with the yield of 90.0%, 82.0% and 92.5% respectively 4 FeS + 7O2 → 2 Fe2O3 + 4 SO2 2 SO2 + O2 → 2 SO3 SO3 + H2O → H2SO4 

Answer 1

Start by writing a balanced chemical equation for the partial ionization of the acid

$HA (aq] + H 2 O (l] ⇌ A − (aq] + H 3 O + (aq]$

Notice that you have 1:1

mole ratios across the board. For every mole of acid that ionizes in aqueous solution, you get one mole of its conjugate base and one mole of hydronium ions, H3O+