Answer to Question #99149 in General Chemistry for john

Question

What mass (g) of BN must be used to produce 125 g of nitrogen triiodide?

Answer 1

$BN+3IF--->NI_3+BF_3$

$Number of moles of BN =Number of moles of NI_3$

$Moles of NI3=125/394.719=0.3167$

$Moles of BN =0.3167$

$Mass of BN=0.3167×24.82$

$Mass of BN=7.86g$ (Answer)