From the combined gas law:
V2(Cl2)=T1p2T2p1V1(Cl2)
V2(Cl2)=298.15∗760273.15∗705∗245=208mL
n(Cl2)=22.40.208=0.009mol From the stoichiometric reaction relationships:
n(MnO2)=n(Cl2)=0.009mol
m(MnO2)=n∗M=0.009∗86.937=0.782g Answer: 0.782 g
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