Answer to Question #99107 in General Chemistry for Shay

Question #99107

What is the heat capacity of gold if a 250 g sample needs 133 cal of energy to increase its temperature from 23.0 degrees Celsius to 40.1 degrees Celsius

Expert's answer

Q=c*m*(t2-t1);

c=Q/[m*(t2-t1)]=133 cal/[0.25 kg*(40.1-23.0)C]=31.1 cal/(kg*C)

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