Answer to Question #99094 in General Chemistry for Lydia

Question #99094
Determine the heat of neutralization of NaOH by HCL
given:
Mass of 1M aq HCl = 100.0g
Mass of 1M aq NaOH = 100.0g
change in temp = 6.91oC
specific heat capacity of .5M aq NaCl = 3.955 J/gram oC
Heat capacity of calorimeter = 43.76 J/oC
1
Expert's answer
2019-11-21T06:25:57-0500

Heat of neutralization, "Q=m*c*\\DeltaT"

where m is the mass of acid, c is the specific heat capacity for aqueous solution,

deltaT is the change in temperature.

Q=(100)g * 3.955J/gram/oC* 6.91oC

Q= 2732.905J/gram


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