Question

Determine the heat of neutralization of NaOH by HCL
given:
Mass of 1M aq HCl = 100.0g
Mass of 1M aq NaOH = 100.0g
change in temp = 6.91oC
specific heat capacity of .5M aq NaCl = 3.955 J/gram oC
Heat capacity of calorimeter = 43.76 J/oC

Answer 1

Heat of neutralization, $Q=m*c*\DeltaT$

where m is the mass of acid, c is the specific heat capacity for aqueous solution,

deltaT is the change in temperature.

Q=(100)g * 3.955J/gram/oC* 6.91oC

Q= 2732.905J/gram