If "T = const = 298K":
"K_p = 1.964*10^{-5}"
Then:
"\\Delta_rH = -RTlnK_p""\\Delta_rH = -8.314*298*ln(1.964*10^{-5})"
"\\Delta_rH = -8.314*298*(-10.84) = 26 856.88 J = 26.86 kJ"
Endothermic reaction; at equal concentrations of CO and CH3OH, the reagents (CO and H2) are in excess.
Accordingly, the equilibrium has shifted towards the formation of reagents. Then the partial pressure of the product decreased, and the partial pressures of the reactants, respectively, increased. Their contribution to overall pressure has also increased.
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