Answer to Question #98714 in General Chemistry for Beverlie

Question

Fe(II) can be precipitated from a slightly basic aqueous solution by bubbling oxygen through the solution, which converts Fe(II) to insoluble Fe(III):

4Fe(OH)^(+) (aq)+ 4OH^(-) (aq) + O2 (g)+ 2H2O (l)→ 4Fe(OH)3 (s)

How many grams of O2 are consumed to precipitate all of the iron in 55.0 mL of 0.0850 M Fe(II)?

Answer 1

n= Cm x V = 0.085 x 0.055 = 0.004675.

32 x 0.004675 /4= 0.0374 g