Molarity=8×10−5μMMolarity= 8×10^{-5}\mu MMolarity=8×10−5μM
Volume=1.25LVolume =1.25LVolume=1.25L
Noofmoles=8×10−5×1.25=10−4μmolesNo of moles = 8×10^{-5}×1.25=10^{-4}\mu molesNoofmoles=8×10−5×1.25=10−4μmoles
Mass of AgO=10−4×123.868=0.0123868=0.012μgAgO=10^{-4}×123.868=0.0123868=0.012\mu gAgO=10−4×123.868=0.0123868=0.012μg (Answer)
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