Question #98715
If the absorbance of a solution of copper(II) ion decreases by 41.00% upon dilution, what volume of water was added to 20.0 mL of a 1.20 M solution of Cu2+(aq)?
1
Expert's answer
2019-11-18T06:28:48-0500

According to a so-called Beer-Lambert law, the absorbance is linearly proportional to the concentration of the solution:


A=eCl;A=eCl;


, where e - absorbance coefficient, C - molar concentration in mol/L and l is a width of the liquid layer.

Thus, we shall try to modify the formula to get the right expression for the concentration of the diluted solution:


A1=eC1l;A_1=eC_1l ;


A2=eC2l;A_2=eC_2l;


η=A1A2A1=el(C1C2)elC1=C1C2C1;\eta=\frac{A_1-A_2}{A_1}=\frac{el(C_1-C_2)}{elC_1}=\frac{C_1-C_2}{C_1};


ηC1=C1C2,\eta C_1=C_1-C_2,


C2=C1(1η),C_2=C_1(1-\eta),


n=C1V1,n=C_1V_1,


С2=nV1+V=C1V1V1+V=C1(1η),С_2=\frac{n}{V_1+V}=\frac{C_1V_1}{V_1+V}=C_1(1-\eta),


V1V1+V=1η,\frac{V_1}{V_1+V}=1-\eta,


Now, we can find a volume of water added:


V=V1(η1η),V=V_1(\frac{\eta}{1-\eta}),


Thus, V=20.0mL(0.4110.41)=13.9mL.V=20.0mL(\frac{0.41}{1-0.41})=13.9mL.


There was 13.9 mL of water added.


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