Answer to Question #96770 in General Chemistry for Hassan

Question #96770
Given the following enthalpy change values for the reactions below: A + 2B → C ; ΔrH = -228.3 kJ mol-1, E + F → 2C + D ; ΔrH = 493.9 kJ mol-1, ½ E → G + 2B ; ΔrH = 314.3 kJ mol-1. Calculate ΔrH for the following reaction (in kJ mol-1) using Hess's Law: 2A + D → F + 2G
1
Expert's answer
2019-10-18T08:58:09-0400

2A + D → F + 2G

∆H= (-228.3)+493.9 - 314.3 = -48.7 kJ/mol


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!

Leave a comment

LATEST TUTORIALS
New on Blog
APPROVED BY CLIENTS