Question #96708
When a 4.00 g sample of KCN is dissolved in water in a calorimeter that has a total heat capacity of 1.94 kJ⋅K−1, the temperature decreases by 0.370 K. Calculate the molar heat of solution of KCN.
1
Expert's answer
2019-10-22T05:44:13-0400

Moles of KCN=465=0.0615molKCN=\frac{4}{65}=0.0615mol

Total heat capacity=n×C×T=n\times C\times∆T

1.94=0.0615×C×0.3701.94=0.0615\times C\times0.370

C=85.25KJmolC=85.25\frac{KJ}{mol}


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