Initial pressure of can"(P_1)=1.52 \\ atm"
Initial temperature of can"(T_1)=22\\degree C=22+273=295K"
Final temperature of Can"(T_2)=935\\degree C=935+273=1208K"
The volume of can remains constant.
Using the equation,
"\\frac{P_1}{T_1}=\\frac{P_2}{T_2}"
Substituting the values,
"\\frac{1.52}{295}=\\frac{P_2}{1208}"
"P_2=6.22\\ atm"
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