Question

if an aerosol can contains a gas at 1.52atm pressure at 22°c, what will be the gas pressure in the can if it is dumped into an incinerator at 935°c?

Answer 1

Initial pressure of can$(P_1)=1.52 \ atm$

Initial temperature of can$(T_1)=22\degree C=22+273=295K$

Final temperature of Can$(T_2)=935\degree C=935+273=1208K$

The volume of can remains constant.

Using the equation,

$\frac{P_1}{T_1}=\frac{P_2}{T_2}$

Substituting the values,

$\frac{1.52}{295}=\frac{P_2}{1208}$

$P_2=6.22\ atm$