Molar mass of ammonium nitrate(NH4NO3)=14+4+14+16×3=80 gm(NH_4NO_3)=14+4+14+16\times 3=80\ gm(NH4NO3)=14+4+14+16×3=80 gm
Number of moles of ammonium nitrate in 10 gm=1080=0.12510 \ gm=\frac{10}{80}=0.12510 gm=8010=0.125
Mass of nitrogen in one mole of ammonium nitrate=14×2=28 gm=14\times 2=28\ gm=14×2=28 gm
Mass of nitrogen in 0.1250.1250.125 moles of ammonium nitrate=0.125×28=3.5 gm=0.125 \times 28=3.5 \ gm=0.125×28=3.5 gm
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