Answer to Question #96643 in General Chemistry for Angel

Question

How much energy (J) is required to heat 24.1 g of water from 23.6 oC to 33.39 oC?

Answer 1

Initial temperature of water$(T_1)=23.6\degree C$

Final temperature of water$(T_2)=33.39\degree C$

Specific heat capacity of water$=4.184 J$

Heat required for the change in temperature$=mC(T_2-T_1)=24.1\times 4.184\times (33.39-23.6)=987.169J$