Moles of "BaSO_4"
As 1 mole of "BaSO_4" contains 1 mole of S , then n(S) = 0.0109 mol
Let the formula of oleum to be "H_2SO_4\\times aSO_3"
Let moles of "H2SO_4" in oleum to be x moles, and of SO3 to be y moles
Then 1 gram of oleum is
Also we know the total moles of S
Solve the system of these two equations:
If a=1 then y= 0.0038, x = 0.0071
If a=2 then y=0.0019, x = 0.0071
If a=3 then y = 0.0013, x = 0.0071
The value of a can be different (1,2,3.....). All these answers are appropriate. It seems like there is lack of data to give accurate answer.
Comments
Leave a comment