Solution.
1.
Write down the reaction equation.
"Ca(OH)2 + 2HClO4 = Ca(ClO4)2 + 2H2O"
Since we need to find the molarity of calcium hydroxide, we can leave the molarity of chloric acid. Translate ml to L.
"C(HClO4)*V(HClO4) = C(Ca(OH)2)*V((CaOH)2)"
"C(Ca(OH)2) = \\frac{C(HClO4)*V(HClO4)}{V(Ca(OH)2)}"
C(Ca(OH)2) = 0.131 M
2.
Write down the reaction equation.
"Ca(OH)2 + 2HNO3 = Ca(NO3)2 + 2H2O"
Since we need to find the molarity of calcium hydroxide, we can leave the molarity of chloric acid. Translate ml to L.
"C(HNO3)*V(HNO3) = C(Ca(OH)2)*V((CaOH)2)"
"C(Ca(OH)2) = \\frac{C(HNO3)*V(HNO3)}{V(Ca(OH)2)}"
C(Ca(OH)2) = 0.1111 M
Answer:
1.
C(Ca(OH)2) = 0.131 M
2.
C(Ca(OH)2) = 0.111 M
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