Answer to Question #96737 in General Chemistry for Angel

General Chemistry

Question #96737

How much energy (J) is required to heat 24.62 g of water from 19.31 oC to 32.22 oC?

Expert's answer

C(H2O) = 4183 J/kg oC.

Q = C(H2O) * m(H2O) * (t2-t1) = 4183 J/kg oC * 0.02462kg * (32.22oC - 19.31oC) = 1329.54J.

Learn more about our help with Assignments: Chemistry

Comments

No comments. Be the first!

Leave a comment

Related Questions

1. Determine the spontaneous reaction between Br2, I2, Br– and I– at 25 °C, Include physical state
2. If the heat of combustion for a specific compound is −1490.0 kJ/mol and its molar mass is 85.69
3. When a 4.00 g sample of KCN is dissolved in water in a calorimeter that has a total heat capacit
4. The balanced combustion reaction for C6H6 is 2C6H6(l)+15O2(g)⟶12CO2(g)+6H2O(l)+6542 kJ If
5. if you combine 370.0 mL of water at 25.00 ∘C and 140.0 mL of water at 95.00 ∘C, what is
6. The specific heat of a certain type of metal is 0.128 J/(g⋅∘C). What is the final temperature
7. Perform the conversions between energy units. 2185 kcal 7.29×106