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Answer to Question #96737 in General Chemistry for Angel

Question #96737
How much energy (J) is required to heat 24.62 g of water from 19.31 oC to 32.22 oC?
1
Expert's answer
2019-10-18T08:06:41-0400

C(H2O) = 4183 J/kg oC.

Q = C(H2O) * m(H2O) * (t2-t1) = 4183 J/kg oC * 0.02462kg * (32.22oC - 19.31oC) = 1329.54J.



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