Question #96544

Sodium only has one naturally occurring isotope, 23Na, with a relative atomic mass of 22.9898 u. A synthetic l, radioactive isotope of sodium, 22Na, is used in positron emission tomography. 22Na has a relative atomic mass of 21.9944 u. A 2.0878 g sample of sodium containing a mixture of 23Na and 22Na has an apparent “atomic mass” of 22.9665 u. Find the mass of 22Na contained in this sample.

Expert's answer

Let x to be fractional abundance of 23Na^{23}Na

Let 1-x to be fractional abundance of 22Na^{22}Na


Then

22.9898x+21.9944(1x)=22.966522.9898x + 21.9944 (1-x) = 22.9665

x=0.9766x= 0.9766

m(23Na^{23}Na )= 2.0878×x=2.0878×0.9766=2.0389g2.0878\times x =2.0878\times0.9766 = 2.0389 g


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