Let x to be fractional abundance of 23Na^{23}Na23Na
Let 1-x to be fractional abundance of 22Na^{22}Na22Na
Then
m(23Na^{23}Na23Na )= 2.0878×x=2.0878×0.9766=2.0389g2.0878\times x =2.0878\times0.9766 = 2.0389 g2.0878×x=2.0878×0.9766=2.0389g