Question

What is the mass of 4.00x10^20 CO2 molecules

Answer 1

Solution.

$\frac{m}{M} = \frac{N}{Na}$

$m = \frac{M \times N}{Na}$

$m = \frac{44 \times 4*10^{20}}{6.02*10^{23}} = 0.03 \ g$

m = 0.03 g

Answer:

m = 0.03 g