Find moles of NaClO4:
As one formula unit contains one sodium ion then n(Na+) =n(NaClO4) = 0.0116 mol
"N(Na^+)=0.0116\\times 6.022\\times 10^{23}=6.99\\times10^{21} ions"
As one formula unit contains one perchlorate ion then n(ClO4-) =n(NaClO4) = 0.0116 mol
"N(ClO_4^-)=0.0116\\times 6.022\\times10^{23} =6.99\\times10^{21} ions"
As one formula unit contains one atom of chlorine then n(Cl) =n(NaClO4) = 0.0116 mol
"N(Cl) = 0.0116\\times 6.022\\times 10^{23} = 6.99\\times10^{21} atoms"
As one formula unit contains 4 atoms of oxygen then n(O) =4*n(NaClO4) = 4*0.0116 mol=0.0464 mol
"N(O) = 0.0464\\times 6.022\\times10^{23} =2.79\\times10^{22} atoms"
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