Cathode:
2H2O +2e- -> H2 + 2OH-
Anode:
2OH-- 2e -> 1/2 O2 + H2O
Overall reaction:
H2O -> H2+ 1/2 O2
Or
2H2O -> 2 H2+ O2
During the electrolysis of aqueous solutions of sodium hydroxide, water decomposes with the
formation of gas-hydrogen and oxygen. Because sodium is an active metal, the standard
electrode potential of a pair of Na/Na+
is -2.71 V, which is much less than the potential of
hydrogen standard electrode, for this reason, water is decomposed at the cathode and
hydrogen is reduced. At the anode, the process of oxidation of hydroxide ions is in progress,
because sodium hydroxide gives an alkaline environment.
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