Given:HgV=5cm3ρ=13.55g/cm3Find:N= ??N=νNA=mNAM=ρVNAM=13.55g/cm3∗5cm3∗6.02∗1023mol−1200.59g/mol≈2.0333∗1023Answer: 2.0333∗1023 atoms\bold{Given:}\\ Hg\\ V = 5 cm^3\\ \rho = 13.55 g/cm^3\\[1ex] \bold{Find:}\\ N = \ ??\\[3ex] N = \nu N_A = \dfrac{mN_A}{M} = \dfrac{\rho VN_A}{M} = \dfrac{13.55g/cm^3*5cm^3*6.02*10^{23}mol^{-1}}{200.59 g/mol} \approx 2.0333*10^{23}\\[1ex] \bold{Answer:} \ 2.0333*10^{23} \ atomsGiven:HgV=5cm3ρ=13.55g/cm3Find:N= ??N=νNA=MmNA=MρVNA=200.59g/mol13.55g/cm3∗5cm3∗6.02∗1023mol−1≈2.0333∗1023Answer: 2.0333∗1023 atoms
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments
Leave a comment