In November 2024
Answer to Question #93338 in General Chemistry for Smon
"2NaNO_3 \\stackrel{t\u00b0}{=} 2NaNO_2 + O_2\\\\\n2KaNO_3 \\stackrel{t\u00b0}{=} 2KNO_2 + O_2\\\\\n2Mg(NO_3)_2 \\stackrel{t\u00b0}{=} 2MgO + 4NO_2 + O_2\\\\\nCa(NO_3)_2 \\stackrel{t\u00b0}{=} Ca(NO_2)_2 + O_2\\\\\n2Pb(NO_3)_2 \\stackrel{t\u00b0}{=} 2PbO + 4NO_2 + O_2\\\\\n2Cu(NO_3)_2 \\stackrel{t\u00b0}{=} 2CuO + 4NO_2 + O_2"
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#339914 on Dec 2023
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