Solution: Mg(s) +2HCl(aq) −→ MgCl2(aq) + H2(g)
Amount: 1mol 2mol
Amount: 4.45mol 2×4.45mol
Amount: 24g 2×(1+35.5)g
Mass of HCl consumed =2×4.45mol = 2×4.45×36.5 g=324.85g
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