All the heat released by the reaction is absorbed by the water:
"\\Delta H_{rxn} = -q_{absorbed}"
"\\Delta H_{rxn} = -315.1 kJ"
"n(C_4H_8) = \\frac{m(C_4H_8)}{M(C_4H_8)} = \\frac{7 g}{56.11\\frac{g}{mol}} = 0.1248 mol"
"\\Delta H_f^0 = \\frac{\\Delta H_{rxn}}{n} = \\frac{-315.1 kJ}{0.1248 mol} = -2525\\frac{kJ}{mol}"
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