n(Cu(NO3)2)=6.68g187.57g/mol=0.0356molesn(Cu(NO3)2)=\dfrac{6.68g}{187.57g/mol}=0.0356molesn(Cu(NO3)2)=187.57g/mol6.68g=0.0356moles
V=nc=0.0356moles0.52mol/L=0.06846L=68.46mLV=\dfrac{n}{c}=\dfrac{0.0356moles}{0.52mol/L}=0.06846L=68.46mLV=cn=0.52mol/L0.0356moles=0.06846L=68.46mL
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