Answer to Question #88052 in General Chemistry for Janell Wilson

Question

If 6.68 g of CuNO3 is dissolved in water to make a 0.520 M solution, what is the volume of the solution?

Answer 1

$n(Cu(NO3)2)=\dfrac{6.68g}{187.57g/mol}=0.0356moles$

$V=\dfrac{n}{c}=\dfrac{0.0356moles}{0.52mol/L}=0.06846L=68.46mL$