Answer to Question #88052 in General Chemistry for Janell Wilson

Question #88052
If 6.68 g of CuNO3 is dissolved in water to make a 0.520 M solution, what is the volume of the solution?
1
Expert's answer
2019-04-15T07:54:22-0400

n(Cu(NO3)2)=6.68g187.57g/mol=0.0356molesn(Cu(NO3)2)=\dfrac{6.68g}{187.57g/mol}=0.0356moles

V=nc=0.0356moles0.52mol/L=0.06846L=68.46mLV=\dfrac{n}{c}=\dfrac{0.0356moles}{0.52mol/L}=0.06846L=68.46mL


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