Question

how much energy is required to melt 256g of ice

Answer 1

The heat of fusion of ice is 333.55 J/g. That means, that for melting 1 g of ice into 1 g of water, we need to conduct 333.55 joules of energy. As we have 256 g of ice, we need 256 times more energy. So, we get an equation:

$$Q=\lambda*m=333.55 J/g * 256 g =85388.8 J$$

where Q - amount of heat energy, lambda - heat of fusion for ice, m - mass of ice.

Answer: we need 85388.8 joules of heat energy to melt 256 g of ice.