Question #87499
A scientist measures the standard enthalpy change for the following reaction to be -112.0 kJ :

2NO(g) + O2(g) ------> 2NO2(g)

Based on this value and the standard enthalpies of formation for the other substances, the standard enthalpy of formation of NO2(g) is _________ kJ/mol.
1
Expert's answer
2019-04-08T07:55:59-0400
ΔHf(NO)=90.25kJmol\Delta H_f(NO)=90.25 \frac{kJ}{mol}

ΔHrxn=ΔHf0(products)ΔHf0(reactants)\Delta H_{rxn}= \sum \Delta H_f^0(products)-\sum \Delta H_f^0(reactants)ΔHrxn=2×ΔHf0(NO2)(2×ΔHf0(NO)+1×ΔHf0(O2))\Delta H_{rxn}= 2\times \Delta H_f^0(NO_2)-(2\times \Delta H_f^0(NO)+1\times \Delta H_f^0(O_2))

112.0kJmol=2×ΔHf0(NO2)(2×90.25kJmol+1×0kJmol)-112.0 \frac{kJ}{mol}= 2\times\Delta H_f^0(NO_2)-(2\times 90.25 \frac{kJ}{mol}+1\times 0\frac{kJ}{mol})

ΔHf0(NO2)=34.25kJmol\Delta H_f^0(NO_2)= 34.25 \frac{kJ}{mol}


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