Answer to Question #87489 in General Chemistry for jay

Question

The reaction of hydrogen chloride(g) with ammonia(g) to form ammonium chloride(s) proceeds as follows:
HCl(g) + NH3(g) --------> NH4Cl(s)
When 12.8 grams of HCl(g) react with sufficient NH3(g) , 61.8 kJ of energy are evolved .

What is the value of H for the chemical equation given?

ΔHrxn = _______ kJ

Answer 1

12.8 g                                            61.8 kJ

 HCl(g) + NH₃(g) --------> NH₄Cl(s) + Q

36.5 g                                              X kJ

Q = X = 36.5 g × 61.8 kJ / 12.8 g = 176.2266 kJ ≈ 176.23 kJ.

ΔH_r = –Q = – 176.23 kJ.

HCl(g) + NH₃(g) --------> NH₄Cl(s);   ΔH_r = – 176.23 kJ.