determine number of oxydation of the following CAPITALS elements
a) O3
b) h3PO4
c)MNo3
d)C2o4 -2
1
Expert's answer
2018-08-03T05:07:15-0400
a) The number of oxydation for O is zero, because O3 is a simple substance. b) The number of oxydation for H is +1, O is -2. The number of oxydation for P we can find by solving equation: (+1)*3+x+(-2)*4=0 x=+5 c) For Mn we have: x+(-2)*3=0 x=+6 d) For C we have: 2x+(-2)*4=-2 x=+3
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