Answer to Question #79447 in General Chemistry for Chloe Lozano

Question #79447
CH3OH + KF → KOH + CH3F is a first order reaction for all of the reactants, with a rate constant of 0.0123 l/Ms. Find the instantaneous rate for this reaction if the initial concentration of CH3OH is 0.59 M, and the initial concentration of KF is 1.22 M.

A. 0.56 1/Ms
B. 0.56 1/M2s
C. 0.0089 M/s
D. 0.0089 M2/s
E. None of the Above
1
Expert's answer
2018-08-07T06:32:05-0400
Rate = k x [CH3OH]^1 x [KF]^1
Initial rate, just bang everything in (since you have initial concentrations):
Rate = 0.0123M-1s-1 x 0.59M x 1.22M = 0.0089 M/s

C. 0.0089 M/s

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Comments

Assignment Expert
31.08.18, 14:11

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Chloe Lozano
30.08.18, 18:39

thank you

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