Answer to Question #79505 in General Chemistry for Mahesh

Question #79505

Find oxidizing number of Fe in Na2(Fe(CN)5 (NO)

Expert's answer

CN has a charge of -1, NO is +1, and Na is +1, so Fe is +2. We can find the oxidation number of Fe by solving equation:

+1*2 + x + (-1)*5 + 1 = 0

x + 3 – 5 = 0

x = +2

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