Answer to Question #73426 in General Chemistry for Sipan Mskeen

Question

20 ml of 0. 2 silver nitrate is needed to titrate 25 ml of chloride solution sample. Calculate the concentration of the chloride ion by g/50ml unite?

If A. Wt of chloride= 35. 5

Answer 1

Solution:
Molarity of chloride solution sample: 0.2 ∙ (20 / 25) = 0.16 M = 0.16 mol/L
Amount of chloride ions in 50 ml of the sample: 0.16 ∙ (50 / 1000) = 0.008 mol
Mass of chloride ions in 50 ml of the sample: 0.008 ∙ 35.5 = 0.284 g
So, the concentration: 0.284 g/50ml

Answer:
0.284 g/50ml