Question #73418, Chemistry / General Chemistry / Completed
A team of geologists has found a possible iron ore source, which happens to be magnetic. They have analysed a 1 kg sample of ore as follows:
The sample was crushed and passed over a magnetic belt to separate magnetite from the nonmagnetic residue. An amount of 345 g of magnetic ore was obtained. The non-magnetic residue was placed in a tank and underwent froth floatation. The lighter, copper-containing material floated while the heavier, silicon-containing material sank. 152 g of copper ore was extracted. Calculate the percentage composition of the original sample, with respect to iron ore and copper ore.
Solution
1000 g of the sample contains 345 g of Fe₃O₄, 152 g of copper ore and 503 g of silicon residue. The percentage composition of the ore:
34,5 % Fe₃O₄ : 15,2 % copper ore : 50,3 % silicon materials.
The content of iron in the sample:
233.547 g of (Fe₃O₄) contains 3 x 55.85 g (Fe)
345 g of (Fe₃O₄) contains x g (Fe)
x = 247.51 g of Fe or about 24.75 %.
Answer: 34,5 % Fe₃O₄ : 15,2 % copper ore : 50,3 % silicon materials; 24.75 % of Fe.
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