Answer to Question #71310 in General Chemistry for Harvir

Question

h2 + 1/2 o2 = h2o Δhm= -286 kj/mol
a. calculate the enthalpy of the reaction
b. include the energy value in the equation

Answer 1

a. The balanced equation:
2 H2 + O2 = 2 H2O, therefore:
the Enthalpy is: (-286) ∙ 2 = -572 kJ
b. Energy released in the reaction = -Enthalpy, so:
2 H2 + O2 = 2 H2O + 572kJ