A 40.8 mol sample of methane gas CH4 is places in a 1020 L container at 298K.
What is the pressure, in atm of the methane gas?
1
Expert's answer
2017-11-22T13:10:07-0500
Use the ideal gas law. From original equation PV=nRT there is P=nRT/V, R=8.31441J/(K∙mol)=0.08206(L∙atm)/(K∙mol), i.e. P (atm) = (40.8 mol*0.08206(L∙atm)/(K∙mol)*298K)/1020 L = 0.9782 atm
Numbers and figures are an essential part of our world, necessary for almost everything we do every day. As important…
APPROVED BY CLIENTS
"assignmentexpert.com" is professional group of people in Math subjects! They did assignments in very high level of mathematical modelling in the best quality. Thanks a lot
Comments
Leave a comment