Answer to Question #342625 in General Chemistry for Rachel

Question

what is the maximum amount of SF₄ that can be made in the reaction 16.87g of NaF and 98.42g of SCI₂

Answer 1

3 SCl2 + 4 NaF = SF₄ + S₂Cl₂ + 4 NaCl

1. We find the amount of NaF substance. for this we use the formula

n = m / M = 16.87 / 42 = 0.4 mol NaF.

Theoretically we find how many moles SF₄ are formed. 

According to the reaction,

1 mole of SF₄ is formed from 4 moles of NaF. How many moles of SF₄ are formed from 0.4 moles of NaF? :

4mol NaF —> 1mol SF₄

0.4mol NaF –> X

X= 0.4 * 1 / 4 = 0.1 mol SF₄.

2. We find the amount of SCl₂ substance. for this we use the formula

n = m / M = 98.42 / 103 = 0.96 mol SCl₂. Theoretically we find how many moles SF₄ are formed. 

According to the reaction,

1 mole of SF₄ is formed from 3 moles of SCl₂. How many moles of SF₄ are formed from 0.96 moles of SCl₂ ? :

3mol SCl₂ —> 1mol SF₄

0.96mol SCl₂ –> X

X= 0.96 * 1 / 3 = 0.32 mol SF₄.

3. In practice, we get the answer in which calculation the least SF₄ is formed. that is, we obtain SF4 (0.1mol) calculated on NaF. because NaF is a limiting reagent in this reaction. (All of the NaF reacts. Some of the SCl₂ increases.)

4. We find the mass of 0.1 mol of SF₄. for this we use the formula m = n * M:

m = n * M_(SF4) = 0.1 * 108 = 10.8 gr

ANSWER: 0.1mol or 10.8gr SF₄