Answer to Question #333406 in General Chemistry for Theheh

Question

If 10 grams of butane(C4H10), afuel in cigarrete lighter, react with 10 grams of O2, how many grams of the product will be formed

Answer 1

2C₄H₁₀ + 13O₂ → 8CO₂ + 10H₂O, n(O2)=0.3125 mol: n(C4H10)=0.1724 mol, the C4H10 is in excess, we have to calculate the mass of products wit using the n of O2.

m(products) = 18*((0.3125*10)/13) + 44*((0.3125*8)/10)=15.327 g of products will be formed