Answer to Question #333277 in General Chemistry for Tafadzwa

Question

Calculate the mass of Na_2O that forms if 4,8g O₂ reacts completely with sodium

Answer 1

Solution:

The molar mass of O₂ is 32 g/mol

Therefore,

Moles of O₂ = (4.8 g O₂) × (1 mol O₂ / 32 g O₂) = 0.15 mol O₂

Balanced chemical equation:

4Na + O₂ → 2Na₂O

According to stoichiometry:

1 mol of O₂ produces 2 mol of Na₂O

Thus, 0.15 mol of O₂ produces:

(0.15 mol O₂) × (2 mol Na₂O / 1 mol O₂) = 0.30 mol Na₂O

The molar mass of Na₂O is 62 g/mol

Therefore,

Mass of Na₂O = (0.30 mol Na₂O) × (62 g Na₂O / 1 mol Na₂O) = 18.6 g Na₂O

Mass of Na₂O = 18.6 g

Answer: 18.6 grams of Na₂O